URGENT Biology lab help needed...EASY question!? - easy biology labs
We had a bio-laboratory, where yesterday I had tubes with a bucket in the liver at each, interspersed with sand and 20 ml of hydrogen peroxide. We have seen what happened in each tube. In the tube 1 in the liver was normal, but in the tube 2, the liver was crushed. In each tube with the same reactions, the two tubes. One of the issues to be addressed to:
How to compare results of the test tube 1 and 2? Is that what she has been the enzyme in liver cells would normally be expected?
I thought that the tube does not react with chopped liver as much as with the whole liver. I do not know how to explain why though. To do something to change the form of the enzyme and not be able to do their job or something. HELP!
Tuesday, December 8, 2009
Easy Biology Labs URGENT Biology Lab Help Needed...EASY Question!?
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I guess the reaction I saw was bubbling with hydrogen peroxide as substrate and enzyme such as peroxidase. With the crushing of the liver, it frees more enzymes in the mixture and thus the formation of enzyme-substrate complex. When the cube is still normal, the enzymes have some kind of movement of its ligand and thus reduces the time and intensity. To destroy, in other words, in the liver, no more "juice of the enzymatic reaction, and much more.
The amount of catalase enzyme for the destruction of the optimal rate of hydrogen is very low. The liver contains enough Uncrashed catalase on the surface of the cut on the optimal rate achieved when the excessive amount of catalase chopped liver.
over the entire surface reaction rate. chopped liver has a larger surface area to react with him, he reacts more quickly? Indeed, the two tubes the same result reached, but the response rates are the same? . exercise
If there is a simple question: "Why can not answer?
If there is a simple question: "Why can not answer?
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